a,b and c can do piece of work in 10,12 and 15 days respectively.A leaves 5 days before the completion of teh work and b leaves days after A.the whole work lasts for

• lets total work last for x daYs.
  so A worked for =x-5 days.
  B worked for = x-4 days.
  and c worked last.
  so
  
  x-5/10 + x-4 /12 + x/15 = 1
  x=110/15days.
• 10 years agoHelpfull: Yes(11) No(3)
• As nothing is given about the number od days after A, that B left, i am assuming it to be 2. Based on that assumption, I am solving the question.
  
  The simple way of solving the question is assuming the total work to be LCM of 10, 12 and 15.
  Let the total work be typing 60 pages, A can do 6/day, B can do 5/day and C can do 4/day
  For the last three days only C worked, so work done = 3*4=12
  The previous two days , B and C worked, so work done = 2(4+5)=18
  The remaining work is done by A,B and C(6+5+4)
  Remaining work= 60-(12+18)=30
  Days required = 30/15 = 2 days
  
  Total time duration= 7 days
• 10 years agoHelpfull: Yes(1) No(4)
• Take total work completed in x days
  
  A=(x-5)/10
  
  B=(x-3)/12
  
  C=x/15
  
  A+B+C= ?
  
  LCM =60
  (6x-30+5x-15+4x)/60
  =7 days
• 7 years agoHelpfull: Yes(0) No(3)