Find a positive number which when increased by 17 is equal to 60 times the reciprocal of the number.

A.
3
B.
10
C.
17
D.
20

• x+17=60/x
  on solving this equation by shri dharacharya formula
  then we have two roots 3 and -20
  so the ans is 3
• 12 years agoHelpfull: Yes(7) No(2)
• X +17 = 60/X.( From the question)
  Substitute all values form the given options.....in X
  Now first Substitute X= 3,,,
  3+17 = 60/ 3
  20 = 20.......... which satisfies the condition..
• 5 years agoHelpfull: Yes(3) No(0)
• A. 3
  lets suppose no. is x now
  according to question =
  x+17=60*(1/x)
  now its form a qudratic eqn
  x^2+17x-60=0
  solution of this eqn is
  x=3,-20
  because in the question positive number is mention so the answer is (A). 3
• 7 years agoHelpfull: Yes(0) No(0)
• Let the no be X . Then X+17=60* 1/X(reciprocal).
  Thus, We get ,
  X=3
• 7 years agoHelpfull: Yes(0) No(0)
• let the answer be X
  X+17=60*1/X
  if u substitute the given options one by one
  ans will be 3
  3+17=60*1/3
  20=20
  so the answer is 3
• 7 years agoHelpfull: Yes(0) No(0)
• x+17=60/x
  x^2+17x=60
  =>x=3 or x=-20
  hence ans is option a
• 6 years agoHelpfull: Yes(0) No(0)
• X+17=60/x
  x^2+17x-60=0
  X^2+20x-3x-60=0
  x(x+20)-3(x+20)=0
  x=3 & x= -20
  Hence A. 3 is answer.
• 5 years agoHelpfull: Yes(0) No(0)
• x+17=60/x
  x^2+17*x-60=0
  x^2+20*x-3*x-60=0
  x(x+20)-3(x+20)=0
  x=3, x=-20
  therefore option a is correct
• 5 years agoHelpfull: Yes(0) No(0)
• Option A is correct
• 5 years agoHelpfull: Yes(0) No(0)