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Maths Puzzle
In the sequence 1, 22, 333, 4444,... the nth term has n number of n's. Then the sum of the digits of the 87th term is
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- for 87 there will be 87878787....87 times
means 8 will be 87 times and 7 will be 87 times
(87*8)+(87*7)
696+609=
1305
ans. 1305 - 11 years agoHelpfull: Yes(2) No(1)
- 878787.....87time
now sum of its digit is=(8+7)*87=1305 - 11 years agoHelpfull: Yes(2) No(0)
- In 87th term there are 2 digits therfore 878787....
since 87th term is odd so there are 46 8s and 47 7s
ie 46*8=368
and 47*7= 329
sum is 368+329 = 697 - 11 years agoHelpfull: Yes(1) No(1)
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