A company has three staff members working in communications department. They are Peter, Satish and Raju. The company has received a work of sending communication to its potential customers. The time the three take to complete the dispatch work together is 2 days less than Peter would have taken to do it alone, 10 days less than Satish to do the work alone and one-third of the time that Raju would have taken working alone. How many days will the three people take to do the dispatch of all the mails working together?

• Answer is 2.
  The values are 2 days together for all the three, 4 days for Peter, 12 days for Satish and 6 days for Raju.
  The question can be solved by forming the equation and solving the equation
  
  The equation will be
  1/x = 1/(x+2) +1/(x+10) + 1/3x
  A quadratic equation has to be solved to obtain the answer.
  
  The question can also be solved by Reasoning.
  Raju has done one-third of the work.
  So, Satish and Peter has done 2/3 of the work.
  So, Answer cannot be 4, as in the casse of 4, peter would have done 4/6 th of the work,and this is not possible.
  Answer also cannot be 1, as in this case Peter would have worked 1/3 of the work, this is also not possible, as peter is more effecient than Satish
  
  By checking the remaining values of 2 and 3, we get 2 as the correct answer
• 11 years agoHelpfull: Yes(15) No(0)
• let total work be 1
  and total days taken by three working together=x days
  then 1 day work of peter=1/(x+2)
  1 day work of satish=1/(x+10)
  1 day work of raju=1/(3x)
  
  totall 1 day work of all three=1/(x+2) + 1/(x+10) + 1/(3x)
  total x days work of all three =x* ( 1/(x+2) + 1/(x+10) + 1/(3x) )
  which is equal to 1(total work).
  
  => 1=x* ( 1/(x+2) + 1/(x+10) + 1/(3x) )
  
  =>x=2,-5
  
  so x=2 is acceptable
  
• 10 years agoHelpfull: Yes(3) No(1)
• A+B+C=1/x
  A=1/x+2
  B=1/x+10
  C=1/3x
  1/x+2 + 1/x+10 + 1/3x =1/x
  solve ans is 2
  
• 10 years agoHelpfull: Yes(2) No(0)