Arun and vinay together can do a piece of work in 7 days if arun does twice as much work

10.5 days
arun = 2(vinay)
2/v + 1/v = 7
v=21
therefore arun = 21/2
10.5 days
10 years agoHelpfull: Yes(7) No(0)
let Arun completes work in x days
then Vinay in 2x days
Arun + Vinay 1 day work=1/x+1/2x=1/7
on solving x=10.5
so Arun will complete work in 10.5 days
10 years agoHelpfull: Yes(5) No(0)
arun takes 21 days alone to do the work
10 years agoHelpfull: Yes(3) No(7)
ans=10.5 days
total time taken by, Arun(A) + Vinay(V) =7 days
=>7days work of A + 7 days work of V
[according to ques, A does twice work for same time => A takes half time for same work]
=>total time taken by A= 7days work of A + 7/2 days work of A(i.e.7 days work of V) = 7 + 3.5 = 10.5 days
10 years agoHelpfull: Yes(1) No(0)
A=2B
1/X+1/2X=1/7
2+1/2X=1/7
3/2X=1/7
2X=21
X=21/2
10 years agoHelpfull: Yes(1) No(0)
vinay(work)=1/2*arun(work)

let arun's work=x therefore arun's one day work will be 1/x

but vinay=arun's/2 or x/2 therefore vinay's one day work will be 1/(x/2)

hence 1/x(arun)+2/x(vinay)=1/7
x=21...
8 years agoHelpfull: Yes(1) No(0)
ratio of work done by arun and vinay =2:1
total work done in=7 days
arun does it in =(2/3)*7=14/3=4days and 6 hours.
10 years agoHelpfull: Yes(0) No(10)
From the question arun's one day work=2* vinay's one day work
So a:b is ratio then a:2a is the format
3a=1/7
a=1/21
So totally 21 days take by arun alone to complete the whole work
3 years agoHelpfull: Yes(0) No(0)

Arun and vinay together can do a piece of work in 7 days.if arun does twice as much work as vinay in a given time how long will arun take to do work