The smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is:

A.
1008
B.
1015
C.
1022
D.
1032

• to obtain the result,
  first we have to calculate the Least Common Multiple (L.C.M) of given numbers 12, 16, 18, 21...
  The L.C.M. = 1008
  Required number = L.C.M + 7
  = 1008 + 7
  = 1015
• 13 years agoHelpfull: Yes(12) No(2)
• b.)1015 as it is divisible by every no..
• 13 years agoHelpfull: Yes(11) No(1)
• L.C.M of 12,16,18,21,28 is 1008
  and it is also divisible by 7
• 13 years agoHelpfull: Yes(7) No(4)
• the answer vl be 1015 as...
  for finding the least num v hv 2 consider the LCM of 12 16 18 21 and 28 and dat is 1008 bt v hv 2 select a num vich has 2 be diminished by 7 also so v take 1008+7=1015
• 13 years agoHelpfull: Yes(3) No(0)
• 1008 is divisible by all the numbers
• 13 years agoHelpfull: Yes(2) No(1)
• go through the negetive approch.
  all the numbers except 1015 is subtrct by 7 then an odd number come that is not divisible by 12,16,18,21 and 28. but when 1015 subtract by 7 then 1008 comes which is divisble by all numbers
  so ans is 1015.
• 13 years agoHelpfull: Yes(2) No(1)
• ans.1008
  because it is divisible by 7 and moreover the number divisible by 12, 16, 18, 21 28 should be firstly divisible by 2,3,7.....and 1008 is the only no which is divisible by 2,3,7
• 13 years agoHelpfull: Yes(1) No(1)
• the correct ans is 1015...option b. when it is diminished by 7 it becomes 1008, which is divisible by 12,16,18,21 and 28 and gives 84,63,56,48 and 36 respectively.
• 13 years agoHelpfull: Yes(1) No(0)
• the answer is 1015
  
• 13 years agoHelpfull: Yes(0) No(0)
• From the options it is clear that the answer is 1015(find the LCM of the given No. add 7 to it)
  But actually 7 is the smallest no. which when diminished by 7 is divisible by the given No.when 7 is diminished by 7, the result is zero and this is divisible by the given Nos.
• 13 years agoHelpfull: Yes(0) No(0)