Find the greatest number that will divide 43 91 and 183 so as to leave the same remainder in each

To get the required solution,
we have to find the highest common factor... and given that it leave the same remainder...
so we have to find the number as follows:
H.C.F. of (91-43),(183-91) and (183-43)
=H.C.F. of 48,92,140 =4.
13 years agoHelpfull: Yes(13) No(3)
A. is the correct option.
the greatest no. that will divide 43,91 and 183 to leave same remainder in each case is 4 and the remainder in each case is 3.
13 years agoHelpfull: Yes(6) No(1)
the number will be a even no. to have a remainder same here... and it is 4...which gives remainder 3 in each case.....
13 years agoHelpfull: Yes(4) No(1)
43%4=3,91%4=3,183%4=3 so ans=4
8 years agoHelpfull: Yes(1) No(0)
43/4 gives remainder 3
91/4 gives remainder 3
183/4 gives remainder 3
10 years agoHelpfull: Yes(0) No(1)
43 ÷ No remainder x
91 ÷ No remainder x
183 ÷ No remainder x
that means (43 – x), (91 – x) and (183 – x) are divisible by required number.
Rule : GCD is also a factor of sum or differences of number
so find subtraction of numbers
91 – 43 = 48
183 – 91 = 52
48 = 4 × 12
52 = 4 × 13
GCD is 4
so required number is 4
43/4 = remainder 3
91/4 = = remainder 3
183/4 = remainder 3
9 years agoHelpfull: Yes(0) No(0)
4 ,the remainder of 43,91,183 is 0 by 4
9 years agoHelpfull: Yes(0) No(0)
hcf[(91-43),(183-91),(183-43)]=4
9 years agoHelpfull: Yes(0) No(0)

Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

A)4
B)7
C)9
D)13