One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:

A.
81 min.
B.
108 min.
C.
144 min.
D.
192 min.

• ANSWER : 144 min
  
  SOLUTION :
  
  Assume that slower pipe take x min
  So faster take x/3 min
  In 1 min both together fill 1/x + 3/x = 4/x
  So x/4 = 36
  Or, x = 144
• 12 years agoHelpfull: Yes(9) No(0)
• Assume A's Speed is 1. then b is 3(three time Faster)
  
  Total =A+B fill in 36m. (capacity is 36X4=144)
  
  Now , a is slower alone fill in 144min. with speed of 1.
  
  So anwser is 144min.
• 8 years agoHelpfull: Yes(1) No(0)