A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?

A.
20
B.
24
C.
30
D.
33

• Answer will be option C
  Let the side of the square be x
  bt walking along side distance will be 2x.
  diagonal, d = sqrt(2)*x (by PGT)
  walking along diagonal is sqrt(2) * x
  percent saved = [(2x - sqrt(2)*x)/2x]*100
  = [(2x - 1.41x)/2x]*100
  = .59x/2x * 100
  = .295 * 100
  = 29.5
  hence option C is the answer
  
• 12 years agoHelpfull: Yes(9) No(3)
• 20 as the area is less
• 8 years agoHelpfull: Yes(0) No(0)
• take side of a square is = 1
  then along square distance will be = 1+1=2
  and the diagonal will be = 1*rut 2=rut 2
  so distance not cover will be = 2 - rut 2
  so the percentage will be = (2 - rut 2) /2*100=(2 -1.6)/2*100=(.4/2)*100=20 as rut 2 approximately 1.6
• 7 years agoHelpfull: Yes(0) No(0)
• Let the side of the square be x
  bt walking along side distance will be 2x.
  diagonal, d = sqrt(2)*x (by PGT)
  walking along diagonal is sqrt(2) * x
  percent saved = [(2x - sqrt(2)*x)/2x]*100
  = [(2x - 1.41x)/2x]*100
  = .59x/2x * 100
  = .295 * 100
  = 29.5
  hence option C is the answer
• 7 years agoHelpfull: Yes(0) No(0)