Two persons A and B started simultaneously from the some point along two roads perpendicular to each other at speed of 40 kmph and 42 kmph. what would be the shortest distance between then after half an hour?

• the shotest distance between them is 29km
  (20^2+21^2)=x^2
  (400+441)=x^2
  so, x^2=841=29*29
  so x=29
• 11 years agoHelpfull: Yes(1) No(0)
• the shortest distance between them is approximately 30km
  
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• 20*20+21*21=x*x
  x=approx 31 km
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• 29 kms.. use pythogoras therom for triangles...
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