Simplify the following (578291*578291-457428*457428)/120863

• by (a2-b2)=(a-b)(a+b)
  (578291+457428)(578291-457428)/(120863)
  =(1035719)(120863)/(120863)=1035719
• 10 years agoHelpfull: Yes(23) No(0)
• let a=578291, b=457428
  a-b=578291-457428=120863
  a+b=578291+457428=1035719
  so given exp is
  (a^2-b^2)/(a-b)=(a+b)*(a-b)/(a-b)=a+b=1035719
  
• 10 years agoHelpfull: Yes(21) No(0)
• in tcs we can use calculators so dont worry about time for these type of problems :)
• 10 years agoHelpfull: Yes(3) No(1)
• (578291^2-457428^2)/(578291-457428)=(578291+457428)*(578291-457428)/(578291-457428)=578291+457428=1035719
• 10 years agoHelpfull: Yes(1) No(0)
• a=578291
  b=457428
  a-b=120863
  (a2-b2)=(a-b)(a+b)
  =(120863)(1035719)
  ((a-b)(a+b))/(a-b)=1035719
• 10 years agoHelpfull: Yes(1) No(0)
• It is of the form (a^2-b^2)/(a-b)
  so the answer is a+b.
  i.e.,578291+457428=1035719
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 1035719
  a^2-b^2=(a+b)(a-b)
  a-b is denominator in cancellation
  a+b is ans =1035719
• 10 years agoHelpfull: Yes(0) No(0)
• a^2-b^2=(a+b)(a-b)
  a+b=578291+457428=1035719
  a-b=120863
  =(1035719)(120863)/120863=1035719
• 10 years agoHelpfull: Yes(0) No(0)
• it is in the form of(a^2-b^2)/(120863)
  (a+b)(a-b)/120863
  (578291+457428)(578291-457428)/120863
  (935719)(120863)/120863
  now,
  120863 will cancel out each other
  ans is935719
• 10 years agoHelpfull: Yes(0) No(1)