Q. If y = x +2, Find the range of real values of y satisfying the inequalities 16x - 6 > 42 and 7x - 24 < 60"

Option
a) 5 < y < 14
b) 3 < y < 12
c) 1 < y < 10
d) y < 10

• 16x – 6 > 42 => 16x >48 => x>3 ...(1)
  And 7x – 24 < 60 = > 7x x 3 and y - 2 5 or y < 14
  Combining the above range, we get, 5 < y < 14
• 10 years agoHelpfull: Yes(20) No(4)
• Firstly we take:
  16x - 6 > 42 and we will reduse it to x+2 form at Left hand side so that it can be written in the form of y as y=x+2.
  16x-6>42
  x-(6/16)>(42/16)
  addind 2 both sides:
  x-(6/16)+2>(42/16)+2
  hence,x+2>5
  as y=x+2
  so,y>5
  similarly,solve 7x-24
• 10 years agoHelpfull: Yes(9) No(1)
• Ans a
  
  Given y=x+2 (then x=y-2)
  
  16 (y-2) - 6 > 42 ( this eq results y>5)
  
  7 (y-2) -24 < 60 ( this eq results y
• 10 years agoHelpfull: Yes(9) No(1)
• ans is option a
• 10 years agoHelpfull: Yes(4) No(0)
• option a is correct
• 10 years agoHelpfull: Yes(1) No(0)
• 16x-6>42
  16x>48
  x>3........(i)
  similarly from 7x-24
• 10 years agoHelpfull: Yes(1) No(0)
• ans is (a)
• 9 years agoHelpfull: Yes(1) No(0)
• ans = (a)542 -> x>42/16 -> x>3
  eq2- 7x-24
• 10 years agoHelpfull: Yes(0) No(0)
• 16x-6>42 => x>48/16 =>x>3.. 7x-247x x
• 10 years agoHelpfull: Yes(0) No(0)
• ans a)
  check all options like this 5
• 10 years agoHelpfull: Yes(0) No(0)
• Option a is the correct one.
• 10 years agoHelpfull: Yes(0) No(0)
• a is correct
• 10 years agoHelpfull: Yes(0) No(0)
• 16x-6>42 and 7x-243 and x5 and y
• 10 years agoHelpfull: Yes(0) No(0)
• solve 16x-6>42 and 7x-24>60 we get x>3 and x
• 10 years agoHelpfull: Yes(0) No(2)
• ans a bcj it sholud be less than 14
  
• 9 years agoHelpfull: Yes(0) No(1)
• Answer is a
  
• 9 years agoHelpfull: Yes(0) No(0)
• Can anyone explain it clearly?
• 8 years agoHelpfull: Yes(0) No(0)
• y=x+2 i.e x=y-2 sustitute x value in 16x-6>42
  16(y-2)-6>42
  16y-32-6>42
  16y-38>42
  16y>80
  y>5
  
  like wise in 7x-24
• 8 years agoHelpfull: Yes(0) No(0)