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Numerical Ability
Age Problem
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, the how old is B?
A. 7
B. 8
C. 9
D. 10
E. 11
Read Solution (Total 13)
-
- A=B+2
B=2c => C=B/2
A+B+C=27
(2+B)+B+(B/2)=27
=> B=10
- 13 years agoHelpfull: Yes(6) No(1)
- ans is option D)10
A=B+2
B=2c => A=2C+2
A+B+C=27
2C+2+2C+C=27
=> 5C=25....==>C=5
So B=2C
B=2(5)=10 - 10 years agoHelpfull: Yes(5) No(1)
- c age x,
then b age is 2x
so a age is 2x+2.
(2x+2)+2x+x=27
5x=25
x=5
so b is 2x=2(5)
ans is 10 - 13 years agoHelpfull: Yes(3) No(1)
- Answer: (D)
Solution:
let C age=x
then B age=2x
and A age=2x+2
A+B+C=27
x+2x+2x+2=27
x=5
so B age is 2x
2*5=10 years. - 13 years agoHelpfull: Yes(3) No(1)
- A=B+2
B=2c => C=B/2
A+B+C=27
(2+B)+B+(B/2)=27
=> B=10
- 10 years agoHelpfull: Yes(3) No(1)
- D. 10
A = 12, B = 10, C = 5.
So, A = B + 2
B = 2C
A+B+C = 27 - 13 years agoHelpfull: Yes(0) No(0)
- b is 10 year old.
- 10 years agoHelpfull: Yes(0) No(0)
- Answer is 10
A+B+C=27
2+B+B+(B/2)=27
B=10 - 9 years agoHelpfull: Yes(0) No(0)
- Let the age of C will be x
Then B=2x
And A= 2x+2
So, total age is given i.e27
Now, x+2x+2x+2=27
X=5
So ans will be 2×5=10
- 9 years agoHelpfull: Yes(0) No(0)
- 10
given,
a=b+2,
b=2c =>c=b/2
a+b+c=(b+2)+b+(b/2)
- 9 years agoHelpfull: Yes(0) No(0)
- 10 is the answer as let b=x then c=x/2 and a=x+2 add all 5x=50 then x=10
- 9 years agoHelpfull: Yes(0) No(0)
- From given problem
A=2+B
and B=2*C
and A+b+c=27
=> 2+B+B+B/2=27
=>5*B/2=25
=>B=5
- 9 years agoHelpfull: Yes(0) No(0)
- (D)
A = B+2
B=2C
A+B+C =2C+2+2C+C =27
C=5
B=10
A=12 - 9 years agoHelpfull: Yes(0) No(0)
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