1!+2!+3!+4!+5!+........50!

• 1! + 2! + 3! + ..... + n! = (n+1)!/n
  
  Ans- 51!/50
• 11 years agoHelpfull: Yes(11) No(12)
• i think there is no direct formula for this question and (n+1)! doesnt works.
  
• 11 years agoHelpfull: Yes(5) No(0)
• 1!+2!+3!+4!+...50!
  =50!(1+1/50+1/49*50+...+1/50!)
  =50!(1+.02+....)
  =50!*1.02(approax)
  =50!*102/100
  51!/50
• 10 years agoHelpfull: Yes(4) No(0)
• take 50! common ,
  50!(1 + 1/50+ 1/50* 49 + ....)= 50! ( 1 + .02 + ..........)= 50!(1.02)= 50!(102/100)
• 10 years agoHelpfull: Yes(2) No(0)
• in these type of questions ,ans is nearly equal the last term i.e 50!..... check this out .... 50 ! is the ans(approx)..... but if we have to apply the exact formula it will be (n+1)!/n i.e 51!/50 ..... the 2nd way is more accurate one..
• 11 years agoHelpfull: Yes(1) No(3)
• (n+1)!/n,and n =50,so the ans is 51!/50
• 11 years agoHelpfull: Yes(0) No(4)
• ans: 50!(51)/50
• 11 years agoHelpfull: Yes(0) No(1)
• Sn= n/2(a+l)
  =50/2(1!+50!)
  
• 11 years agoHelpfull: Yes(0) No(3)