z is a number in decimal system that z = 260*1024 + 73*512 +128*129 +81 +9.Let y be te octal representation of z .how many times will the digit 3 be there in y .
option
1. 2
2. 3
3. 4
4. 5

• The above decimal expression can be written as:-
  
  8(260*128 + 73*64 + 129*16 + 11) + 2 -- take aside remainder 2
  8(260*16 + 73*8 + 129*2 + 1) + 3 -- take aside remainders 32
  8(260*2 + 73 + 32) + 3 -- remainders 332
  8(65 + 4 + 9) + 1 -- remainders 1332
  8(9) + 6 -- remainders 61332
  8(1) + 1 - remainders 161332
  finally the number ion octal = 1161332
  Ans : 2
• 11 years agoHelpfull: Yes(45) No(0)
• easy solution for dis question is like:
  since y is octal represention of z, and z is decimal so 1st solve equation z.
  z=(260*1024)+(73*512)+(128*129)+81+9
  = 26624+ 37276 + 16512 +81 + 9
  = 80602
  Now convert dis 80602 in octal by dividing dis number by 8,
  u will get 234132
  
  so 3 exist 2times.
• 11 years agoHelpfull: Yes(21) No(11)
• First lets convert everything into the highest power of 8 visible in the question, that is 512.
  
  S0, it can be written as 520 * 512 + 73 * 512 + 128 * (128+1), the reason for changing the 128 expression is to convert it also into 512.
  So, the expression is 512 * 520 + 512 * 32 + 512 * 32( which is 128/4)
  
  So, that will result as 512 * 625
  Now this will help in finding all the digits from 4 th digit, the method is
  dividing 625 by 8, the quotient is 78 and remainder is 1
  dividing 78 by 8, the quotient is 9 and the remainder is 6
  dividing 9 by 8, the quotient is 1 and the remainder is 1
  
  So, the first four (from right) digits of the octal expression are 1161.
  
  Now the sum of remaining three numbers is 128 + 81 +9 = 218
  
  If we divide it by 8, the quotient is 27 and remainder 2
  If 27 is divided by 8, the quotient is 3 and remainder is 3
  
  So, the last three digits are 332
  
  So, the entire number is 1161332
  The number of 3's is two
  Answer is two
  
• 11 years agoHelpfull: Yes(9) No(0)
• 260*(2^10)+ 73*(2^9)+129*(2^7)+90
  2^7*(260*8+73*4+129)+90
  16*8*(2501)+90
  16*20008+90
  320128+90=320218
  change this to octal value by deviding 8 you will get (1161332)base8
  here we got 2 times 3.
• 11 years agoHelpfull: Yes(5) No(0)
• solving the value for z we get
  z= 80602
  converting it to octal we get 235332
  
  So the answer is 3 digit will be there 3 times.
• 11 years agoHelpfull: Yes(2) No(3)
• ARCHNA Explain How?
• 11 years agoHelpfull: Yes(1) No(0)
• 1. 2 3's
  just convert z into binary and then convert binary into octal,and see the total no. of 3's
• 11 years agoHelpfull: Yes(0) No(5)
• ise bina binary me convert kiye bhi direct octal me convert kiya ja sakta hai.
• 11 years agoHelpfull: Yes(0) No(1)
• Himanshu Kaise????
  
• 11 years agoHelpfull: Yes(0) No(0)
• i guess its 4
  
• 11 years agoHelpfull: Yes(0) No(1)
• Normally multiplying numbers in z, we get 316291
  and then converting it to octal we get 111132 which means only one 3 is there.
  so options are wrong.
• 9 years agoHelpfull: Yes(0) No(1)