1*1!+2*2!+3*3!+....+2012*2012!=??

• n*n!= (n+1)!-n!
  Therefore, 1*1!+2*2!+...+2012*2012!=2!-1!+3!-2!+...2013!-2012!
  = 2013!-1!
• 10 years agoHelpfull: Yes(36) No(0)
• 2013!-1
  FORMULA THERE
  
• 10 years agoHelpfull: Yes(8) No(0)
• 1*1!= 1= 2!-1!
  2*2!= 4= 3!-2!
  3*3!=18= 4!-3!
  4*4!=96=5!-4!
  ..... similarly 2012*2012= 2013!-2012!
• 10 years agoHelpfull: Yes(5) No(8)
• n*n!=(n+1)!-n!
  Similarly 2012*2012!=2013!-2012!=2013
  Ans is 2013.
• 10 years agoHelpfull: Yes(1) No(3)
• 2013! - 1 is the sum
  
• 10 years agoHelpfull: Yes(0) No(0)
• from formula ...(n+1)!-1
  so,1*1!+2*2!+3*3!+...........+2012*2012!=(2012+1)!-1=2013!-1
• 10 years agoHelpfull: Yes(0) No(0)
• n*n!= (n+1)!-n!
  Therefore, 1*1!+2*2!+...+2012*2012!=2!-1!+3!-2!+...2013!-2012!
  = 2013!-1!
• 9 years agoHelpfull: Yes(0) No(0)