The maximum number of points in the intersection of an arbitrary circle and the function y = 2 sin x is

• range of y = 2 sin x is [-2,2]
  if we take radius of circle just less than 2,then circle cuts the geaph of 2sinx at 4 points,this will be maxm for an arbitrary circle.
  ans 4
• 11 years agoHelpfull: Yes(13) No(3)
• infinity ...
• 11 years agoHelpfull: Yes(5) No(6)
• 2 one at positive x axis and other on negative side
  
• 11 years agoHelpfull: Yes(1) No(8)
• 4,
  Since Maximum points of intesection will be obtain at a circle of radius 2
• 10 years agoHelpfull: Yes(0) No(1)