AGE
*OAT
------------------
SOAR
HOG.
GOTO..
------------------
GECOIR

• 317
  538
  ---------
  2536
  951
  1585
  --------
  170546
  ---------
• 11 years agoHelpfull: Yes(9) No(1)
• Can you please explain how you assign the value for each number????
  
• 11 years agoHelpfull: Yes(8) No(0)
• 317
  *538
  _____
  2536
  951
  1585
  _____
  170546
• 11 years agoHelpfull: Yes(2) No(1)
• 317
  538
  ____
  
  2536
  951
  1585
  _____
  170546
• 10 years agoHelpfull: Yes(1) No(0)
• 1) AGE * T = SOAR
  2) AGE * A = HOG ( i.e A is a small no.)
  3) AGE * O = GOTO ( here E * O gives O, so O can be either 0 or 5, but O can not be 0 as AGE * 0 = 000 (OOO); this implies O is 5 & E is an odd no.)
  so putting O as 5 we have AGE * 5 = G5T5 (from here we have G * 5 does not generates a carry as A * 5 gives G5 and that's possible only if G=1 (A1E*5=15T5) which implies A=3)
  so now the crypt is like ->
  31E
  x 53T
  --------
  S53R
  H51x
  15T5xx
  ----------
  1EC5IR ( from here we have I = (3+1) = 4 and C = (5+5+5) = )
  
  Again from 31E * 3 = H51 ( i.e. E * 3 = 1 + carry =2 as next 1 * 3 =3 + carry =5 which left us with the fact that E * 3 = 21 so E = 7. and again we have 3 * 3 = 9 == H; one more thing 317 * 5 = 1585 so T=
  now we have
  317
  x 538
  ----------
  S53R
  951x
  1585xx
  ----------
  17C54R
  and now it looks easier
  1) 317 * 8 = 2536 (so S = 2, R = 6)
  
  2) So, the result will be 170546 and Thus C= 0
  
  0.C
  1.G
  2.S
  3.A
  4.I
  5.O
  6.R
  7.E
  8.T
  9.H
  
  Hence The Problem Is Solved. QED
• 10 years agoHelpfull: Yes(1) No(0)