What is the largest integer that divides all three numbers 23400,272304,205248 without leaving a remainder?

• 24
  Finding the prime factors of numbers
  23400=3*3*2*2*2*5*5*13
  272304=3*3*2*2*2*2*31*61
  205248=3*2*2*2*2*2*2*1069
  Now HCF=3*2*2*2=24
  
• 11 years agoHelpfull: Yes(20) No(0)
• answer is 24
• 11 years agoHelpfull: Yes(2) No(1)
• 24
  Finding the prime factors of numbers
  23400=3*3*2*2*2*5*5*13
  272304=3*3*2*2*2*2*31*61
  205248=3*2*2*2*2*2*2*1069
  Now HCF=3*2*2*2=24
• 11 years agoHelpfull: Yes(1) No(0)
• last 2 unit place are divide by 4 so 4 is answer
• 11 years agoHelpfull: Yes(0) No(9)
• i think the 1st number is 234000...
  
  ok solve it as it is given
  
  There is a trick to solve this type of qus
  to find the largest number that will divide given numbers say X1,X2,...Xn so as to leave the same remainder in each case , we find the HCF of positive difference of numbers ie X1-X2 , X2-X3,... and so on.
  
  
  solving this qus we will get the ans 8....
• 11 years agoHelpfull: Yes(0) No(8)
• 24 is the answer according to prime factarization
  
• 8 years agoHelpfull: Yes(0) No(0)