SEND+MORE=MONEY?
how to solve it...plz explain clearly..

• 9 5 6 7
  1 0 8 5
  ----------
  1 0 6 5 2
  ----------
• 10 years agoHelpfull: Yes(3) No(4)
• S=9m
  R=9n
  D=y
  E=O=0
• 10 years agoHelpfull: Yes(0) No(3)
• http://s4.zetaboards.com/science/topic/7693756/1/
• 10 years agoHelpfull: Yes(0) No(0)
• We see at once that M in the total must be 1, since the total of the column SM cannot reach as high as 20. Now if M in this column is replaced by 1, how can we make this column total as much as 10 to provide the 1 carried over to the left below? Only by making S very large: 9 or 8. In either case the letter O must stand for zero: the summation of SM could produce only 10 or 11, but we cannot use 1 for letter O as we have already used it for M.
  
  If letter O is zero, then in column EO we cannot reach a total as high as 10, so that there will be no 1 to carry over from this column to SM. Hence S must positively be 9.
  
  Since the summation EO gives N, and letter O is zero, N must be 1 greater than E and the column NR must total over 10. To put it into an equation: E + 1 = N
  
  From the NR column we can derive the equation: N + R + (+ 1) = E + 10
  
  We have to insert the expression (+ 1) because we don’t know yet whether 1 is carried over from column DE. But we do know that 1 has to be carried over from column NR to EO.
  
  Subtract the first equation from the second: R + (+1) = 9
  
  We cannot let R equal 9, since we already have S equal to 9. Therefore we will have to make R equal to 8; hence we know that 1 has to be carried over from column DE.
  
  Column DE must total at least 12, since Y cannot be 1 or zero. What values can we give D and E to reach this total? We have already used 9 and 8 elsewhere. The only digits left that are high enough are 7, 6 and 7, 5. But remember that one of these has to be E, and N is 1 greater than E. Hence E must be 5, N must be 6, while D is 7. Then Y turns out to be 2, and the puzzle is completely solved.
  
• 9 years agoHelpfull: Yes(0) No(0)