not geting it Distribute 10 different pencils among 3 students

There are 10 pencils.Let us assume these are 10 pencils is to be distributed among 3 students,so put two partitions in between these 10 pencils anywhere
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now add these partitions to the pencils so total it becomes 12
nCr will be the number of ways where n = 12 (total object + partition),r = 2(number of partition)
So, 12C2 = 66.
11 years agoHelpfull: Yes(16) No(4)
this question is similar to finding number of functions that can be formed between two sets A and B .n(A)=10,n(B)=3..so..number of functions =3 power 10.
11 years agoHelpfull: Yes(10) No(0)
3^10
11 years agoHelpfull: Yes(9) No(1)
3^10
directly by formula r^n
10 years agoHelpfull: Yes(6) No(0)
arrangement of 10 diffrnt pncil among 3 i.e 10p3=!n/n-r!=10!/7!=720
11 years agoHelpfull: Yes(5) No(8)
is the answer is 120
11 years agoHelpfull: Yes(4) No(4)
number of pencils is 10.
number of students is 3.

10c3 = 10*9*8/1*2*3 = 120
11 years agoHelpfull: Yes(3) No(0)
10p3....as different pencils......think bro
11 years agoHelpfull: Yes(3) No(1)
please submit the answer
11 years agoHelpfull: Yes(2) No(0)
it is a distributed permutation where n non distinct things to r distinct group
formula::(n-1)C(r-1)
9C2 =36 ans
10 years agoHelpfull: Yes(1) No(1)
ans will be 3^10
10 years agoHelpfull: Yes(1) No(1)
10C3=120 is the answer
11 years agoHelpfull: Yes(0) No(2)
10p3=720
10 different pencils among 3 students.so the total number of ways are 720
10 years agoHelpfull: Yes(0) No(1)
10!/(2!*3!*5!)=2520
10 years agoHelpfull: Yes(0) No(1)

not geting it....Distribute 10 "different" pencils among 3 students??