The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly added. The first number is 18 grater than the actual number and the second number added is 13 instead of 31. Find the correct average.

• tOTAL AVERAGE IS 40.2. THE SUM OF TOTAL NUMBERS IS 40.2*10=402. GIVEN 1ST NO IS 18 GREATER , SO SUBTRACT IT 402-18=384.
  SIMILARILY GIVEN THAT 13 INSTEAD OF 31, SO ADD (31-13=18). 384+18=402.
  
  SO ANS IS 402/10=40.2
• 11 years agoHelpfull: Yes(3) No(0)
• 40.2 itself
  Total of 10 numbers=10*40.2=402
  If first correct no.is x then incorrect number=(x+18),actual difference=-18
  The second correct no. 31,incorrect number=13, actual difference=31-13=+18
  So correct average=402-18+18/10=40.2
• 11 years agoHelpfull: Yes(1) No(0)