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what is the average of the first 200 terms of the series 1,-2,3,-4,5,-6,7....
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- average of the first 200 terms of the series 1,-2,3,-4,5,-6,7...
=1+(-2)+3+(-4)+...+199+(-200)/200
=(1-2)+(3-4)+(5-6)+...+(199-200)/200
=(-1)+(-1)+(-1)+...100times/200
=-100/200
=-0.5 - 11 years agoHelpfull: Yes(81) No(0)
- 1,3,5.... are in A.P. sum=n/2{(2a+(n-1)d}
n=100 a=1 d=2 sum= 10000
on the similar fashion -2,-4.....
n=100 a=-2 d=-2 sum =-10100
-10100+10000=-100
so avg.= -100/200 = -.5
- 11 years agoHelpfull: Yes(16) No(0)
- 1+3+5....199=10000
-2-4-6-8....-200=-10100
add both of them
-100
now avg=-100/200= -1/2 will be ans - 11 years agoHelpfull: Yes(3) No(0)
- (1+3+5+7+9+-------+199)-(2+4+6+8+---------+200)
on adding each term we get -100 as the value
so avg= -100/200=-0.5 - 11 years agoHelpfull: Yes(3) No(0)
- Sum of first N odd numbers: 1,3,5,7...200
N^2
N=100=>10000
Sum of first N even numbers:2,4,6,8,...200
N^2 + N=>10000+100=>10,100
so for -2,-4,..-200=>-10,100
10000-10100=-100;
Avg=-100/200
so 0.5
- 11 years agoHelpfull: Yes(3) No(0)
- series can be divide into two i,e 1,3,5,7.... and -2,-4,-6....
so sum of 1st series=10000 and 2nd is -10100
so total sum=10000-10100=-100
avg=-100/200=-0.5 - 11 years agoHelpfull: Yes(1) No(2)
- =1+(-2)+3+(-4)+...+199+(-200)/200
=(1-2)+(3-4)+(5-6)+...+(199-200)/200
=(-1)+(-1)+(-1)+...100/200
=-100/200
=-0.5 - 6 years agoHelpfull: Yes(1) No(0)
- consider two number and add u find only 1
there are 200 numbers
all the sum is 100
to find out average 100/200=0.5 - 11 years agoHelpfull: Yes(0) No(0)
- it is 1-2=-1
3-4=-1
.... 100 times
100 * -1 = -100
avg -100/200= -1/2 - 11 years agoHelpfull: Yes(0) No(0)
- cause here it provide 1 after each block of (-,+) so 100
- 9 years agoHelpfull: Yes(0) No(0)
- 1,-2,3,-4........ So answer is -0.5
- 8 years agoHelpfull: Yes(0) No(0)
- Average of first 200 terms
1+(-2)=1-2=-1
-1+3=2
2+(-4)=2-4=-2
-2+5=3
3+(-6)=3-6=-3
-3+7=4
4+(-8)=-4-8=-4
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100+(-200)=100-200=-100
So sum of first 200 terms=-100
Average of first 200 terms=-100/200
=-0.5 - 8 years agoHelpfull: Yes(0) No(0)
- sum of every 1 pair of no after 1 is 1
till 200 there are 99 pairs so total sum till 199 terms =100
the 200th term is -200 as every even no is -ve
sum till 200 terms=100-200=-100
avg=-100/200=-0.5 - 7 years agoHelpfull: Yes(0) No(0)
- 10 dssdsdsdsddssds
- 6 years agoHelpfull: Yes(0) No(0)
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