There are two statement:
1) 4n-2 is a squire no.
2)5n-3 is a squire no.
option
a) both can be possible
b) 1 can be possible but 2 cant be
c) both cant be possible
d) 2 can be possible but 1 cant be

• both cant be possible,
  a square no. is always of the form 4n or (4n+1),so (4n-2)cant be square of a no.
  and (5n-3) always gives 2 or 7 a unit place,which is not possible for a square no.
  so option(c)
• 11 years agoHelpfull: Yes(100) No(1)
• one correction, n is any natural number
• 11 years agoHelpfull: Yes(2) No(2)
• if n=11/4 than its make perfct sqre.
  if n=7/5 than its make perfct sqre.
  
• 11 years agoHelpfull: Yes(1) No(15)
• both cant be possible
• 11 years agoHelpfull: Yes(1) No(0)
• option c is correct.
• 11 years agoHelpfull: Yes(0) No(0)
• Keshav please update the status of you problem as solved by Rakesh
• 11 years agoHelpfull: Yes(0) No(0)
• both can be possible
  suppose 4n-2=a^2
  hence n= (a^2+2)/4
  and same for the second
  
• 10 years agoHelpfull: Yes(0) No(1)
• (c) both cant be possible.
• 9 years agoHelpfull: Yes(0) No(0)
• both cannot be possible
  
• 9 years agoHelpfull: Yes(0) No(0)