What are the total number of divisors of 600 (including 1 and 600)?

Option
a.24
b.40
c.16
d.20

• 600=2*2*2*3*5*5,p=3,q=1,r=2
  so number of factors=(p+1)(q+1)(r+1)=4*2*3=24
• 11 years agoHelpfull: Yes(43) No(0)
• If N=a^p*b^q*c^r.... then the number of factors of N = (p+1)(q+1)(r+1) ....
  600 = 2^3×3×5^2
  So number of factors of 600 = (3+1)(1+1)(2+1) = 24
  option(a)
  or divisiors of 600 are
  1*600
  2*300
  3*200
  4*150
  5*120
  6*100
  8*75
  10*60
  12*50
  15*40
  20*30
  24*25
  total=24
  
• 11 years agoHelpfull: Yes(28) No(2)
• 600 = 1 x 600 ( Now breaking 600 into prime numbers)
  2 x 300
  2 x 150
  2 x 75
  3 x 25
  5 x 5
  We got three 2s,one 3 and two 5s
  Formula to find number of factors of a number= (p+1)x(q+1)x(r+1)
  where p=3
  q=1
  r=2
  Anser: (3+1)x(1+1)x(2+1)
  4x2x3 = 24 .. Answer = 24
• 11 years agoHelpfull: Yes(12) No(0)
• option a- 24
  since, 600=2*2*2*3*5*5
  So factor are = 2^3,3^1,5^2
  so no. of factor=(3+1)(1+1)(2+1)= 24
• 11 years agoHelpfull: Yes(7) No(0)
• Sol: Option a
  If N=ap×bq×cr.... then the number of factors of N = (p+1)(q+1)(r+1) ....
  600 = 23×3×52
  So number of factors of 600 = (3+1)(1+1)(2+1) = 24
• 11 years agoHelpfull: Yes(4) No(0)
• answer is a.24
• 11 years agoHelpfull: Yes(3) No(0)
• Total 24 divisors 1,2,3,4,5,6,8,10,12,15,20,24,25,30,40,50,60,75,100,120,150,200,300,600
• 11 years agoHelpfull: Yes(3) No(1)
• ans:24
  600=2^3*3^1*5^2
  (3+1)*(2+1)*(1+1)=24
  
• 11 years agoHelpfull: Yes(2) No(0)
• 600=2*2*2*3*5*5=2^3*3^1*5*2=(3+1)*(1+1)*(2+1)=16
• 11 years agoHelpfull: Yes(1) No(6)
• 600=2^3*3^1*5^2
  hence total factors are=(3+1)*(1+1)*(2+1)=24
• 11 years agoHelpfull: Yes(1) No(0)
• 24
  600=2^3*3^1*5^2
  NO.OF DIVISORS=(3+1)(1+1)(2+1)=24
• 11 years agoHelpfull: Yes(1) No(0)
• 2^3*5^3=600
  hense total no of divisors are =(3+1)*(3+1)
  =4*4
  =16
• 11 years agoHelpfull: Yes(0) No(3)
• answer is a....
  
• 11 years agoHelpfull: Yes(0) No(1)
• 24=(3+1)(2+1)(1+1)
  
• 11 years agoHelpfull: Yes(0) No(0)
• 24
  so 4*2*3=24
• 11 years agoHelpfull: Yes(0) No(0)
• 600=2*2*2*3*5*5,p=3,q=1,r=2
  so number of factors=(p+1)(q+1)(r+1)=4*2*3=24
• 8 years agoHelpfull: Yes(0) No(0)
• 600=2*2*2*3*5*5
  so 2^(3)*3^(1)*5^(2)
  =(3+1)*(1+1)*(2+1)
  24.
• 7 years agoHelpfull: Yes(0) No(0)
• 24, by finding all divisors.
• 6 years agoHelpfull: Yes(0) No(0)
• 600=2*2*2*3*5*5
  =(2^3)(3^1)(5^2) from (p^a)(q^b)(r^c ) ,p=2,q=3,r=5,a=3,b=1,c=2
  total number of divisors is
  = (a+1)(b+1)(c+1)
  = (3+1)(1+1)(2+1)
  =4×2×3
  =24
• 3 years agoHelpfull: Yes(0) No(0)