abhishek started from Bangalore to kysore and aishwarya from opposite direction. They met at a resturant mid way and had lunch for 30 minutes. Abhishek travelled 180 km more than aishwarya. After they departed abhishek took 2 hrs to reach kysore and aishwarya 4.5 hours. If they traveled with uniform speed. wat will be the distance between two cities?

• let aishwarya travels x km in order to meet abhishek with speed bkm/hr,
  abhishek travelled 180km more, i.e distance travelled by abhishek= x+180, with speed a km/hr.
  
  time(abhi)=time(aish)
  x/b=(x+180)/a -----(1)
  
  now,the 2nd condition i.e after lunch-
  distance that aish has to travel is x+180km and time taken by her is 4.5hr
  abhi has to travel x km and in 2hrs
  so,
  
  2=x/a i.e
  a=x/2
  
  and 4.5=(x+180)/b
  b=(x+180)/4.5
  
  substitute these values of a and b in equation (1)
  
  4.5x/(x+180) = 2(x+180)/x on solving we get x=360.
  
  so total distance is x+x+180=900
• 10 years agoHelpfull: Yes(25) No(1)
• Total hr=2+4.5=> 6.5 hrs.
  so, if they both travelled at 70km/hr means then abishek travelled dist=315 and aish travelled distance=140.
  but 315-140=175 dist abishek travelled more..(condition is 180)..
  so now take 71km/hr, so abi travelled =319.5 and aish travelled=142
  their diff. is 177.5..
  now take 72km/hr abi travelled=324 and aish travelled=144
  and abishek hv travelled 180 km more than aishwarya now...
  so total distance = 144+324... so 468
• 11 years agoHelpfull: Yes(20) No(11)
• x^2-288x-25920=0
  from this equation x=360.
  and total distance coverd by abhishek is {(180+x)till restro}+{(x)from restro to kysore}.
  so 180+x+x=180+2x.
  tatal distance=180+2*360=900.
  
  
• 11 years agoHelpfull: Yes(8) No(2)
• let speed of abhishek is a and of aishwarya is b
  Distance traveled by aishwarya till restaurant be x
  So distance traveled by abhishek is x+180
  Time(abhishek)=Time (aishwarya) /*till restaurant*/
  so x+180/a = x/b;
  also, after passing restaurant
  for abhishek a= x/2 ;
  and for aishwarya b = x+180/4.5;
  three equations will result to
  2x+360/x = 4.5x/x+180
  solving this result will be eqn 2.5x*x -720x -64800 = 0;
  how to get answer after this..
  options are
  1) 720
  2) 540
  3) 480
  4) 360
• 11 years agoHelpfull: Yes(7) No(4)
• Let, distance traveled by aishwarya = x km
  distance traveled by abhishek = (x+180) km
  
  to reach aishwarya's initial location, abhishek travels x km in 2 hrs. and
  aishwarya travels (x+180) km in 4.5 hrs to reach abhishek's initial position.
  
  Given, Abhishek's speed = Aishwarya's speed
  x/2=(x+180)/4.5
  x=144
  
  So total distance = x + (x+180)= 468 km
• 10 years agoHelpfull: Yes(7) No(4)
• ans is 900
  abhishekmeeet point
  abhishek speed =180 km/hr
  aishwarya speed =120 km.hr
  u can check all condition
• 11 years agoHelpfull: Yes(2) No(1)
• There is a small proof that can be helpful for this particular question.
  
  The ratio of times after meeting will be the square of the reciprocal of the ratio of the speeds
  So, Aishwarya's time/Abhishek's time = (speed of abhishek)^2/ (speed of aishwarya) ^ 2
  
  The other proof that will help is the time for which they travelled before meeting will be square root of the product of two times
  
  So, from the first one ratio of their speed is 1.5
  From the second one, they travelled for 3 hours before meeting
  
  In three, hours with 1.5 times speed abhishek travelled 180 km more.
  As the ratio of the distances is also 1.5(based on the speeds), their distances are 540 and 360
  As they together covered the total distance , the total distance is 900
  
  Answer is 900
  
  
• 11 years agoHelpfull: Yes(2) No(1)
• there is one more option 900.....
• 11 years agoHelpfull: Yes(1) No(0)
• answer is 900.after solve this eq 5x^2-1440x-129600=0 we get x=360 and -72 so the right ans is 900
• 11 years agoHelpfull: Yes(1) No(1)
• Answer is 900 or 468?
• 11 years agoHelpfull: Yes(1) No(0)
• correct answer:900 km
• 10 years agoHelpfull: Yes(1) No(0)
• There is a method to find speed ratio by Given time= S1/S2=(T2/T1)Square Root
  S1=Speed of Abhishek , T1= Time of Abhishek
  S2= Speed of Aishwarya , T2= Time of Aishwarya
  
  Speed Ratio=(4.5/2)^2=3:2
  
  Let the total Distance therefore is X,
  3X/5-2X/5=180
  X=900 Ans
• 2 years agoHelpfull: Yes(1) No(0)
• ANS-540
  --avshek-=(x+180)km---->
• 11 years agoHelpfull: Yes(0) No(1)
• as harshvardhan's procss if we put 360 in d eqn we can gt d ansr nd d middl term fctr would be x^2-360x+72x-25920=0 nd atlst d ansr is is 360
• 11 years agoHelpfull: Yes(0) No(0)
• ans is i think 360
• 11 years agoHelpfull: Yes(0) No(7)
• Total travel time=2+4.5-0.5=6 hrs
  Distance covered by abhishek is 180km in 2 hrs so his speed becomes 90kmph
  therefore distance b/w bang. and kysore will be = 90kmph * 6hr = 540Km.
  
• 10 years agoHelpfull: Yes(0) No(4)
• how ever speed of both are not equal but they take same time when first meet so we equal first (x+180/a)=(x/i) after we know time so 2=x/a and 4.5=(x+180)/i after solving we get x=360 so total distance is 2x=180=900 and speed of a is 180 and speed of i is 120 check all conditions with these values it satisfies
• 10 years agoHelpfull: Yes(0) No(0)
• k.Arun gandu jab nehi ata tho solution mat da
  m.c
• 9 years agoHelpfull: Yes(0) No(1)
• guys dont be confuse 900 will be right if u wannb be sure
  find speed it will 180kmph and 120kmph
  u can put the value nd this will satisfy the condition.
  360+360+180=900
• 7 years agoHelpfull: Yes(0) No(0)
• Time Ratio=(2/4.5)^1/2=2:3
  Speed Ratio=3:2
  Let X is the total Distance therefore,
  3X/5-2X/5=180
  X=900
• 7 years agoHelpfull: Yes(0) No(0)