A number consists of two digits. If the digits interchange places and the new number is added to the original number, then the resulting number will be divisible by:

A.
3
B.
5
C.
9
D.
11

• if the no. is xy then on interchanging the digits it will be yx
  then adding yx in xy it is (x+y)(x+y) which is divided by two digit no. having same digits
  example we have 24 then on interchanging 42 then after adding 66 and it is divided by 11 and always the no. divided by 11
• 13 years agoHelpfull: Yes(4) No(3)
• let,the two digit no is x+10y.if the digits interchange the new no will be 10x+y.now according to information:x+10y+10x+y=11x+11y=11(x+y).so the resulting number is 11(x+y)and it is divisible by 11. (ans D.)
• 12 years agoHelpfull: Yes(4) No(1)
• answer D. 11
  
  eg 12 reverse is 21 add both 33
  19 reverse is 91 add both 110
  
  so all are divide by 11
• 11 years agoHelpfull: Yes(1) No(1)
• Let the ten's digit be x and unit's digit be y.
  
  Then, number = 10x + y.
  
  Number obtained by interchanging the digits = 10y + x.
  
  (10x + y) + (10y + x) = 11(x + y), which is divisible by 11
• 6 years agoHelpfull: Yes(1) No(0)
• let the ten's digit be x and unit's digit be y.
  
  Then, number = 10x + y.
  
  Number obtained by interchanging the digits = 10y + x.
  
  (10x + y) + (10y + x) = 11(x + y), which is divisible by 11.
• 9 years agoHelpfull: Yes(0) No(0)
• ans:d if we take that no as xy &their interchange no is yx.so xy+yx so it is divide by same no in two digit.eg 23 interchange no is 32 so 23+32=55 it is divide by 11.
• 7 years agoHelpfull: Yes(0) No(0)
• ans .D(11)
  take example of 31 reverse of the nunmber is 13 then nuber is added to first number 31+13=44 is divisible by 11.
• 7 years agoHelpfull: Yes(0) No(0)