The children cycled between Camp A and Camp B which are 500 m apart in 50 seconds. If they wanted to reduce the time to 40 seconds, what is the increase in speed?

• present speed 50/5=10m/s
  in order to finish in 40 sec....speed=(10+x)=500/40=x=2.5
  increase in speed is 2.5 m/s
• 11 years agoHelpfull: Yes(1) No(0)
• speed=500/50=10m/s
  let speed is increased by x m/sec
  then (10+x)=500/40
  or 10+x=12.5
  or x=2.5 m/sec
• 11 years agoHelpfull: Yes(1) No(0)
• 500/50=10 m/s
  time =40
  500/40 =12.5 m/s
  12.5-10=2.5 m/s increased
  
• 11 years agoHelpfull: Yes(0) No(0)