how many numbers are there in between 100 to 400 ,in which adding any of two digit then the sum is equal to third digit.

• 51 is the right answer 100% suree guys..
  **for last digit 1 there is 1 possibility 101 and rearrange it 110 so total-[2] **same for 2 ( 112,121,211,202,220 )---[5]
  **same for 3 ( 123,132,213,231,312,321,303,330) --- [8]
  **same for 4 (134,143,314,341,224,242)--- [6]
  ** same for 5 ,6,7,8 and 9 all have [6] possibilities ----- finally (2+5+8+6+6+6+6+6+6 = 51 ) Answer
  
• 10 years agoHelpfull: Yes(21) No(2)
• let take an arrangement three nos like
  |a|b|c|
  in this condition is number should be greater than 100 so we can fix a=1 in first condition
  (0-9)
  |
  |1|b|c|->(0-9) we have equn 1+b=c; or 1+c=b or c+b=1; like this arrangement we can get 9*2 no i.e 18
  similarly if we fix a=2;
  2+b=c; or 2+c=b; or b+c=2; like this we have 8*2+1=17 nos.
  similarly fix a=3;
  we have eqn 3+b=c;or 3+c=b; or b+c=3;
  like this we have 7*2+2=16 nos
  so finally we total ans=18+17+16=51; 100% sure
  
• 10 years agoHelpfull: Yes(17) No(0)
• 51
  
  100% sure its correct
• 10 years agoHelpfull: Yes(10) No(1)
• 51 is the right answr
• 10 years agoHelpfull: Yes(5) No(0)
• I think the answer is 26...
• 10 years agoHelpfull: Yes(3) No(12)
• no reshav ...mainly i have put the question here and there is no any condition that only last digit is sum of other two and the option is
  a)27
  b)30
  c)41
  d)51
  
  and if u count then the answer is 51 but if any one know the short trick then please share because if u go for counting then it takes lot of time...
  
  and thanks to all for ur valuable comments
• 10 years agoHelpfull: Yes(3) No(0)
• 51 is correct
• 10 years agoHelpfull: Yes(2) No(0)
• The Answer is 51....
• 10 years agoHelpfull: Yes(2) No(0)
• 101 ,112 , .... 189 ( 1 at 1st place ) total are 9 numbers
  202 , 213 , ....279 ( 2 at 1st position ) total are 8 numbers
  303 , 314 , ....369 ( 3 at 1st postion ) total are 7 numbers
  unit ,tens digit are interchanged then number doubles hence
  total = ( 9 + 8 + 7 )*2 = 48
  
• 10 years agoHelpfull: Yes(2) No(2)
• Can You explain
• 10 years agoHelpfull: Yes(1) No(0)
• ans: 33
  100-200: 11 nos
  201-300: 11 nos
  301-400: 11 nos
• 10 years agoHelpfull: Yes(1) No(6)
• i think there is no no. betn 100 & 400
  adding any of two digit gives sum equal to third digit.
  ans zero
  
• 10 years agoHelpfull: Yes(1) No(30)
• Sorry for the confusion, the following is the solution for numbers 100 to 400
  
  Last digit 1 : First two digits (1,0) 1 possibility
  Last digit 2 : First two digits (2,0) (1,1) 2 possibilities
  Last digit 3 : First two digits (3,0) (2,1) (1,2) 3 possibilities
  Last digit 4 : First two digits (3,1) (2,2) (1,3)
  Last digit 5 : First two digits (3,2) (2,3) (1,4)
  
  As the first digit cannot be more than 3, for each of last digits 6,7,8 and 9 also we get three numbers each
  
  So, total possibilities = 27
  
  Answer is 27
  
  
• 10 years agoHelpfull: Yes(1) No(6)
• answer is 46
  
  101
  110
  112
  121
  123
  132
  134
  143
  145
  154
  156
  165
  167
  176
  178
  189
  198
  202
  213
  220
  224
  235
  242
  246
  253
  257
  264
  268
  275
  279
  286
  297
  303
  314
  325
  330
  336
  341
  347
  352
  358
  363
  369
  374
  385
  396
  
• 10 years agoHelpfull: Yes(1) No(5)
• Question is not cleared, it must be precised,...."in which adding any of two digit then the sum is equal to third digit".....it tells that we can take any two digits out of three then sumation must be equal to the rest one, which is not possible or it cause problem to understand.
• 10 years agoHelpfull: Yes(1) No(1)
• any of two digit......not frst two is condition here.......n sum sld be equal to the thrd......nt neccsry eql to the digit at unit place.......i thnk no such no exist.......
• 10 years agoHelpfull: Yes(1) No(0)
• The last digit can be any number from 1 to 9.
  
  If the last digit is 1, the first two digits should be (1,0), one possibility
  If the last digit is 2, the first two digits should be (2,0),(1,1) two possibilities
  If the last digit is 3, the first two digits should be (3,0),(2,1) and (1,2) three possibilities
  If the last digit is 4, the first two digits should be (4,0),(3,1), (2,2) and (1,3) two possibilities
  
  Similarly, if the last digit is 9, there 9 possibilities, (9,0) (8,1) (7,2) (6,3)(5,4)(4,5)(3,6)(2,7)(1,8)
  
  So, total number of possibilities = 1+2+3+4+5+6+7+8+9 = 45 numbers
• 10 years agoHelpfull: Yes(0) No(4)
• If we go counting wise starting from 100, such nos. are
  112
  123
  134
  145
  156
  167
  178
  .
  ..
  .
  .
  235
  246
  257
  268
  274
  .
  .
  .
  347
  358
  369
  
  The answr is 22
• 10 years agoHelpfull: Yes(0) No(4)
• 101
  112
  123
  134
  145
  156
  167
  178
  189
  202
  213
  224
  235
  246
  257
  268
  279
  303
  314
  325
  336
  347
  358
  369
  
  http://www.referralduty.com/index.php?invite=31681
• 10 years agoHelpfull: Yes(0) No(1)
• 101,112,123,134,145,156,167,178,189
  202,213,224,235,246,257,268,279
  303,314,325,336,347,358,369
  total=26
• 10 years agoHelpfull: Yes(0) No(7)
• rakesh etna e likh deta same as above lolz
  copy cat
• 10 years agoHelpfull: Yes(0) No(3)
• 101,112,123,134,145,156,167,178,189
  202,213,224,235,246,257,268,279
  303,314,325,336,347,358,369
  total=9+8+7=24
• 10 years agoHelpfull: Yes(0) No(5)
• sushant read the condition last digit must be sum of two
• 10 years agoHelpfull: Yes(0) No(0)
• Answer is 24
• 10 years agoHelpfull: Yes(0) No(1)
• @vaibhav
  in which elitmus test it was asked?
• 10 years agoHelpfull: Yes(0) No(0)
• @just 27 nov
• 10 years agoHelpfull: Yes(0) No(0)
• Answer is 16+17+16=49
• 10 years agoHelpfull: Yes(0) No(0)
• Bhai log, series ban jaega count karna padega, aur koi option nai hae
• 10 years agoHelpfull: Yes(0) No(0)
• may be 0. there is no number between 100 & 400
• 10 years agoHelpfull: Yes(0) No(1)
• awesome answer ashraf bhai
• 10 years agoHelpfull: Yes(0) No(0)
• visit this for solution http://www.onlineadhyayana.com/ elitmus section...:)
• 10 years agoHelpfull: Yes(0) No(0)
• Can anyone plz explain me the solution of Md Asif Ashraf
• 10 years agoHelpfull: Yes(0) No(0)
• I think if 100th place is fixed for 1,2 and 3
  then for 1 "101" can be arranged in 2 ways.
  .
  . . 101,112,123,134,145,156,167,178,189=2*9=18
  similarly 202,213,224,235,246,257,268,279=2*8=16
  303,312,314,325,336,347,358,369=2*8=16
  therefore ans=18+16+16=50
• 10 years agoHelpfull: Yes(0) No(0)