Q. Find the number of different ways in which 7^11 can be expressed as the product of three factors.

• let 7^11=7^x*7^y*7^z
  then possible triplets of (x,y,z)
  (0,0,11)(0,1,10)(0,2,9)(0,3,8)(0,4,7)(0,5,6)
  (1,1,9)(1,2,8)(1,3,7)(1,4,6)(1,5,5)
  (2,2,7)(2,3,6)(2,4,5)
  (3,3,5)(3,4,4)
  so number of different ways=16
• 10 years agoHelpfull: Yes(95) No(15)
• (0,1,10)(0,2,9)(0,3,8)(0,4,7)(0,5,6)
  (1,1,9)(1,2,8)(1,3,7)(1,4,6)
  (2,3,6)(2,4,5)
  no of diff ways 11
  by applying permutations,by fixing 1 st factor we can get easily..
  
• 10 years agoHelpfull: Yes(1) No(11)
• hey frnds plz explain clearly plz
  
• 10 years agoHelpfull: Yes(0) No(2)
• it is more than 16,please explain right answer...
• 10 years agoHelpfull: Yes(0) No(1)
• 7^11= 7^x + 7^y + 7^z. number of cases where x+y+z=11 are 45.
• 10 years agoHelpfull: Yes(0) No(3)