A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2109 sq. m, then what is the width of the road?

A.
2.91 m
B.
3 m
C.
5.82 m
D.
None of these

• B. 3 m
  Total area of park= 60*40= 2400sq.m
  Lawn area = 2109 sq.m
  That means there is a difference of 291 sq.m(this is the area of the two cross roads). Lets take 'x' as the width of the road.
  ie, 60*x + 40*x - (x*x) = 291
  100x - 2x =291
  98x =291
  x = 2.96
  ie, x =3
  
  
  
  
• 12 years agoHelpfull: Yes(10) No(1)
• area with out cross roads=60*40=2400 m
  area excluding cross roads area(area of lawn)=2109 m
  
  so area occupied by cross roads=291m
  
  
  ___||___
  ___||___ cross roads in the rectangular park
  ||
  
  40+60=100 (length+width)
  100*3=300
  
  300-(3*3)=300-9=291 [at meeting point of cross roads, either length or width only considered. so, substract a square of 3X3]
  
  
  
• 13 years agoHelpfull: Yes(4) No(2)
• Area of the park = (60 x 40) m2 = 2400 m2.
  
  Area of the lawn = 2109 m2.
  
  Area of the crossroads = (2400 - 2109) m2 = 291 m2.
  
  Let the width of the road be x metres. Then,
  
  60x + 40x - x2 = 291
  
  x2 - 100x + 291 = 0
  
  (x - 97)(x - 3) = 0
  
  x = 3.
  
• 10 years agoHelpfull: Yes(4) No(0)