If A speaks the truth 60% of the times, B speaks the truth 50% of the times. What is the probability that at least one will tell the truth

• probability of A speaks truth p(A)=6/10;false=4/10
  probability of B speaks truth p(B)=5/10;false=5/10.For given qtn
  Ans=1-(neither of them tell truth).Because A & B are independent events
  =1-[(4/10)*(5/10)]=4/5=0.8
• 11 years agoHelpfull: Yes(55) No(1)
• atleast one telling truth=1-neither of them tell tuth
  1-(40/100 +50/100)=1/10
• 11 years agoHelpfull: Yes(3) No(14)
• AT means a truth
  AF means AF like that wise
  there can be three case
  (AT,BF) (AF,BT) (AT,BT)
  .6*.5+.4*.5+.6*.5
  =.8
  
• 10 years agoHelpfull: Yes(3) No(1)
• [3/5*1/2]+[3/5*1/2]+[2/5*1/2]=0.8
• 11 years agoHelpfull: Yes(1) No(2)
• 1-(neither of them tell truth)=0.8
  
• 11 years agoHelpfull: Yes(1) No(0)
• A-->p1=3/5,q1=2/5;
  B-->p2->1/2,q2=1/2;
  ans---> P1.p2+p1.q2+q1.p2------>4/5;
  or both false --->q1.q2=2/5*1/2=1/5----->any one is true at least --->1-1/5=4/5;
• 7 years agoHelpfull: Yes(1) No(0)
• ans is o.8
• 11 years agoHelpfull: Yes(0) No(0)
• 1-(4/10*5/10) = 0.8
• 11 years agoHelpfull: Yes(0) No(0)