self
Maths Puzzle
Put 21 balls in 4 boxes such that each box will have odd number of balls.
Read Solution (Total 2)
-
- The probability will be zero, because if all the boxes have odd number of balls, then the total must be an even number.
So, with 21 balls, at the most three boxes can be odd numbers
Answer is zero - 11 years agoHelpfull: Yes(3) No(1)
- 3+3+5+7=21
- 10 years agoHelpfull: Yes(2) No(0)
self Other Question