Jake is faster than Paul. Jake and Paul each walk 10 km.Jake reaches to destination 1.5 less than time taken by paul. Then paul speed is equal to :

• From the options given in the TCS exam..........Assume Jake speed=4kmph..then,he will reach destination in 2.5hrs. then,paul speed will be 2.5kmph.and he covers thedidtsnce in 4hrs. Then, Jake speed will be more than paul.
• 11 years agoHelpfull: Yes(19) No(0)
• Data insufficient.......
• 11 years agoHelpfull: Yes(4) No(1)
• explain please
• 11 years agoHelpfull: Yes(2) No(0)
• let jake speed be 2x and paul 's x.
  w.k.t speed =distance/ time
  so jake speed is2x=10/0.5t and paul speed is x=10/t. on dividing these eqs we get
  2=0.5 . tat implies paul speed is 0.5 km/h.and 2 implies tat jake is 2 times faster than paul.
• 11 years agoHelpfull: Yes(2) No(8)
• Question z not correct..
• 11 years agoHelpfull: Yes(2) No(0)
• 0.5 Times more jake
• 11 years agoHelpfull: Yes(1) No(7)
• jake is faster in his speed in covering the same distance . so distance in both the cases would be the same.we knw speed = distance/time.
  let speed be x and time be t.
  jake spped is x=10/0.5t . paul speed is 2x=10/t . divide these eqs we get
  o.5=0.5. L.H.S= R.H.S. so ans is 0.5 km/sec
• 11 years agoHelpfull: Yes(0) No(10)
• let t=time, paul speed is (t/(t+1.5)) times to speed of jack
• 11 years agoHelpfull: Yes(0) No(2)
• Let jake's speed= s
  and time taken by jake=t
  paul's speed= x
  => st=x(t+1.5)
  =>x=st(t+1.5)
  which implies paul speed is (t/(t+1.5)) times to speed of jack
• 9 years agoHelpfull: Yes(0) No(1)
• Speed=Timedistance
  let the speed of joke x then speed of paul will be 7-x
  24x+247−x=14
  Try to plugin the values from the options. If Joke speed is 4 the paul is 3.
• 9 years agoHelpfull: Yes(0) No(0)
• 6 is the answer
• 8 years agoHelpfull: Yes(0) No(0)