Log( X+3 ) + log ( X + 5 ) = log 35

• log( X+3 ) + log ( X + 5 ) = log 35
  or log[(x+3)*(x+5)]=log35
  or (x+3)*(x+5)=35
  or x=2,-10 (but x=-10 is not applicable)
  so x=2
• 10 years agoHelpfull: Yes(3) No(0)
• log (a)+log (b)=log(ab)
  so,if we put x=2.then it validates the equation.
• 10 years agoHelpfull: Yes(1) No(0)
• log m + log n =log m*n
  so log(x+3)(x+5)=log 35
  (x+3)(x+5)=35
  x^2+x+15=35
  x^2+x-20=0,
  (x+5)(x-4) =0
  x=4,-5
  
• 10 years agoHelpfull: Yes(0) No(1)