Find the missing term in the seqence: 325, 446, 567, ___, 709, 820.

• 688
  Only unit digit considered after adding 1,2,1 to 3 digits respectively
  325
  (3+1)(2+2)(5+1)=446
  (4+1)(4+2)(6+1)=567
  (5+1)(6+2)(7+1)=688
  (6+1)(8+2)(8+1)=709
  (7+1)(0+2)(9+1)=820
• 10 years agoHelpfull: Yes(3) No(0)
• 325+121=446
  446+121=567
  567+121=682
• 10 years agoHelpfull: Yes(2) No(0)
• every series first number increse by 1
  3,4,5,6,7,8
  every series second number increse by 2
  2,4,6,8,0,2
  every series first number increse by 1
  5,6,7,8,9,0
  then arrange the series
  325,446,567,688,709,820 ans:688
• 10 years agoHelpfull: Yes(0) No(0)
• answer=688 because in digits +1,+2,+1 is added
• 10 years agoHelpfull: Yes(0) No(0)