i have to numberd my house such that if it is a multiple of 3 than numberd (50 to 59) and if it not divisible by 4 than can numberd (60 to 69)........

Que.1- what can be my house number
(a)51 (b)63 (c)64 (d) All of the above

• we have to 1st consider multiple of 3,if its not then apply 2nd condition not divisible by 4
  51 is divisible by 3 but not by 4,satisfies both condition,cant be number twice
  a)51 is multiple of 3 so must numbered betn 50 to 59(T)
  b)63 is multiple of 3 so must numbered betn 50 to 59(F)
  c)64 is not multiple of 3,but multiple of 4,so it cant be house number(F)
  d)all of above(F)
  ans(a)
• 10 years agoHelpfull: Yes(54) No(1)
• go through options
  since 51 is multiple of 3,not of 4 so house no. should within(50 to 59)
  also 64 is divisible by 4 so lies betn (60 to 69),it contradicts given condns
  option(a)
  
• 10 years agoHelpfull: Yes(15) No(6)
• 51 means divisible by 3 and betwn(50-59)
  63 means divisible by 3 but not betwn(50-59)
  64 means divisible by 4 and given if NOT divisible by 4 then betwn(60-69)
  so ans is 51
  
• 10 years agoHelpfull: Yes(6) No(0)
• b, it is because 63 does not lie between 50 and 59 and is multiple of 3 and also it is not divisible by 4.
• 10 years agoHelpfull: Yes(5) No(7)
• i think question has a little mistake,
  
• 10 years agoHelpfull: Yes(3) No(1)
• 51
  since other options are not possible..
• 10 years agoHelpfull: Yes(0) No(1)
• y it can't be option b..it is a multiple of 3 andi is not divisble by 4 ad is between (60 to 69) satsfyng ,2 nd condition?
  
• 10 years agoHelpfull: Yes(0) No(1)
• ans: 51(a)
  multiple of 3 and not divisible by 4
• 10 years agoHelpfull: Yes(0) No(2)
• a will be ans
  51 is divisible by 3
  frt cnd apply.
• 10 years agoHelpfull: Yes(0) No(3)