TCS
Company
Numerical Ability
Number System
.(2988)^647^241 last 3 digits
Read Solution (Total 12)
-
- for last 3 digits calculate 988^3
then last 3 digits will be 272 - 11 years agoHelpfull: Yes(11) No(5)
- 988^3=964430272.
So,the last 3 digits are 272. - 11 years agoHelpfull: Yes(3) No(3)
- 2988/100 gives remainder 88.
647*241=155927
this 155927/4 gives remainder 3
therefore 88^3=681472
last 2 digits are 72. - 11 years agoHelpfull: Yes(1) No(10)
- not appropriate sudheera ji
- 11 years agoHelpfull: Yes(1) No(0)
- please explain answer
- 11 years agoHelpfull: Yes(1) No(1)
- could any 1 give proper resolution of finding last 2 -3 digit of any expression
- 11 years agoHelpfull: Yes(1) No(0)
- how u solved please elaborate
- 11 years agoHelpfull: Yes(0) No(1)
- the last digit is to be considered.(2988)6647^241=(2988)^155927=(2988)(2988)^155926
2988(2988)^2^7763
if we consider the last digit which is 8..then 8^3=512 - 11 years agoHelpfull: Yes(0) No(4)
- can anybody explain the whole concept ??
- 11 years agoHelpfull: Yes(0) No(0)
- why 988^3 ???
- 10 years agoHelpfull: Yes(0) No(0)
- pls do explain how 988^3? will it be applicable for other problems of such type?
- 10 years agoHelpfull: Yes(0) No(0)
- plzz give a proper solution with explaination
- 10 years agoHelpfull: Yes(0) No(0)
TCS Other Question