16+17+18+19+......
+102= ?
YOU HAVE ONLY 1 MIN!

• 87*59=5133
• 11 years agoHelpfull: Yes(1) No(1)
• (87/2)*(16+102)=87*59=5133
  
  total no of terms are 87
  sum of n terms if 1st and last terms r known is (n/2)*(a+l)
• 11 years agoHelpfull: Yes(1) No(0)
• (86/2)*(16+102) = 5074
• 11 years agoHelpfull: Yes(0) No(0)
• since in AP.a=16,d=1,l=102
  n/2[a+l]=51*118=6018.
• 11 years agoHelpfull: Yes(0) No(0)
• there are in total 87 no.s between 16 and 102 (including 16)
  so, by the formula of sum of n terms : n/2(2a+(n-1)d)
  87/2(2*16+(87-1)1)
  87/2(32+86)
  87*59
  =5133
• 11 years agoHelpfull: Yes(0) No(0)
• U can also use (n*(n+1))/2..
  (102*(102+1))/2 = 5253
  but series starts with 16 .so,
  (15(15 +1))/2 = 120
  therefore ans= 5253-120 = 5133.
  but simplest is using sum of n terms
• 11 years agoHelpfull: Yes(0) No(0)
• this is an a.p. series so,
  firstly find the no. of terms by formula of a.p.-
  l=a+(n-1)d
  102=16+n-1
  n=87
  sum in a.p.=n/2[2a+(n-1)d]
  =87/2[2*16+86]
  =87*59=5133
  
• 11 years agoHelpfull: Yes(0) No(0)