A man has four sons .there are 6 proposals of marriage for his sons. In how many ways can they select a proposal for their marriages,such that none of them marry with more than one girl.

Option
a) 180
b) 270
c) 360
d) none of these

• Ans: iii.360
  If the first son selects any of 6,so the second is left with remaining 5...the third left with remaining 4 and the fourth has to select from remaining 3.
  So no. of ways to select the proposal = 6*5*4*3 = 360
• 10 years agoHelpfull: Yes(3) No(1)
• 6*5*4*3= 360 ways
• 10 years agoHelpfull: Yes(1) No(1)
• none of these
• 10 years agoHelpfull: Yes(0) No(3)