If x-y = 7, find the value of (x^2+y^2).

• this is nothing but pithogorian triplets.
  consider 5,12,13 the difference is 7 (12-5).
  then apply pithogorian principle then
  5^2 +12^2= 13^2
  so the answer is 13^2=169
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• taking square on both sides the equation becomes (x-y)^2=(x^2+y^2)-2 x y but the value of 2 x y is not known
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• do u hav any options ?
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