ABCD is a parallelogram G is a point on AB such that AG=2GB, E is a point on DC such that CE=2DE and F is a point on BC such that BF=2FC Prove that
(i)ar(ADEG)=ar(GBCE)
(ii)ar(EGB)=1/6 ar(ABCD)
(iii) ar(EFC)=1/2 ar(EBF)
(iv) ar(EBG)=ar(EFC)

• ar(ADEG)=ar(GBCE)
• 11 years agoHelpfull: Yes(0) No(0)