1223334444112222333333444........... 2001 term in sequence????

• 1223334444=10 terms
  11222233333344444444=20 terms
  Sn=10+20+30+....+10*n=10(1+2+3+...+n)
  if n=19,Sn=10*19*20/2=1900
  if n=20,Sn=10*20*21/2=2100
  so after 1900 there will be 111...(20times)222...(40times)333...(60times)
  so 2001th term is 3
  ans 3
• 10 years agoHelpfull: Yes(48) No(3)
• 1223334444-10TERMS
  11222233333344444444-20 TERMS2
  1111222222223333333333334444444444444444-30 TERMS
  ......
  NUMBER OF TERMS =10[1+2+3..........]
  THIS SUM SHOULD BE LESS THAN 2001
  10*[n(n+1)/2]
• 10 years agoHelpfull: Yes(5) No(0)
• 1223334444=10 terms
  11222233333344444444=20 terms
  Sn=10+20+30+....+10*n=10(1+2+3+...+n)
  if n=19,Sn=10*19*20/2=1900
  if n=20,Sn=10*20*21/2=2100
  so after 1900 there will be 111...(20times)222...(40times)333...(60times)
  so 2001th term is 3
  ans 3
• 10 years agoHelpfull: Yes(4) No(3)
• 1223334444=10 terms
  11222233333344444444=20 terms
  111222222333333333444444444444=30 terms
  then
  so given series can be written as (10 20 30 40 ...........)=>10(1 2 3 4 ......)
  now we have to find 2001 term
  1 2 3 4 are natural numbers
  10*[n(n+1)/2]
• 10 years agoHelpfull: Yes(2) No(1)
• here the sequence is like 10,20,30,40..... terms
  by using the formula 10*n(n+1)/2 let here n=20 then no.of terms in that sequence is 2100 i.e., 21-1's and 42-2's and 63 -3's and 84-4's if we subtract 2100-84=2016 but here 3's lie b/n (1974,2016) there by we can easily say that 2001 term in sequence is 3
  
• 10 years agoHelpfull: Yes(2) No(2)
• 2001 term is 2
  1223334444=10 terms
  11222233333344444444=20 terms
  1111222222223333333333334444444444444444-40 TERMS
  so each time it doubles
  10
  20
  40
  80
  160
  320
  640
  1280
  2560
  it exceeded
  number of 1's in
  1 in 10
  2 in 20
  4 in 40
  256 in 2560
  so 1280+256 = 1536
  number 2's are double than the 1's
  512 2's in 2560
  so 1536+512 = 2048
  so finally 2001 term is 2
• 10 years agoHelpfull: Yes(2) No(6)
• answer is 4
• 10 years agoHelpfull: Yes(1) No(0)
• 1 22 333 4444 (10 terms)
  11 2222 333333 44444444 (20 terms)....subsequently 30 terms,40,50....so on.
  now
  
  these no. of terms add up to 2000 after 20 such sets exactly. (Sn formula)
  
  therefore 2001 the term will be starting of another new set starting with 1
  
  ans. 1
  
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• can any one explain why after 1900 there will be 111...(20times)...
  plz.....can any one answer...
• 9 years agoHelpfull: Yes(0) No(0)
• i think d answer shud be 3.....
  
• 9 years agoHelpfull: Yes(0) No(0)
• after 1900, there will be 20times 1 bcz, from the series given,
  after 10 times 1 is multipled by 2, no of terms series will be 10,20,40,80,160,320,640,1280,2560, so for 2001th term 10*2
  so 1=10*2=20,2=2*10*2=40,3=3*10*2=60
• 9 years agoHelpfull: Yes(0) No(0)