How many digits formed using 1,2,3,4 & 5. (If repitation is possible)

• one digit-5
  two digit-5^2
  3 digit-5^3
  4digit-5^4
  5 digit-5^5..the total is addition of all those numbers
• 10 years agoHelpfull: Yes(37) No(2)
• 5(SINGLE DIGIT)+25(TWO DIGIT)+125(THREE DIGIT)+625(FOUR DIGIT)+3125(FIVE DIGIT)=4025(ANSWER)
• 10 years agoHelpfull: Yes(10) No(5)
• 5^5
  when repetition allowed =n^r
• 10 years agoHelpfull: Yes(6) No(2)
• 5^5 digits=3125 can be formed
• 10 years agoHelpfull: Yes(3) No(1)
• As per the given question,first digit=5ways,second digit=5ways......fifth digit=5ways
  so the answer is 5C1*5C1*5C1*5C1*5C1=5*5*5*5*5=5^5=3125.
• 10 years agoHelpfull: Yes(3) No(0)
• 3245
  
  repetition is possible means each number can come 5 times + all numbers together
• 10 years agoHelpfull: Yes(2) No(0)
• each place can be filled in 5 ways thus its 5*5*5*5*5=5^5
• 10 years agoHelpfull: Yes(2) No(1)
• when repition is possible then no.of digits formed is 5^5
  
  for suppose here they ask how many 4 digits can formed the the ans is 5 ^4.....
  
• 10 years agoHelpfull: Yes(1) No(0)
• Don't Know
• 10 years agoHelpfull: Yes(1) No(2)
• 5^5
  bcoz in every position of the digit we can use that number again..
  suppose a 5 digit number *****,,in 1st position I can use any number from 1,2,3,4,5,,so no. of choices is 5 to make a one digit no. ..similarly in 2nd position I can also use any number from 1,2,3,4,5 since repetition is allowed.. so to make a two digit total no of choices 5*5 .. to make five digit 5^5..uff!! i think this solution is helpful.. :)
• 10 years agoHelpfull: Yes(1) No(0)
• 5^5 digits can be formed
• 10 years agoHelpfull: Yes(1) No(0)
• Ans: 5 digits are formed
  Exp: in the question asked for digits not for numbers ....
  Digit means containing only one digit
• 10 years agoHelpfull: Yes(1) No(0)
• without repetition means simply n^n.
• 10 years agoHelpfull: Yes(1) No(0)
• n P r = n!/(n-r)! = 5 P 5 = 5!/0! =120
  5 P 4 = 5!/1! = 120
  5 P 3 = 5!/2! = 60
  5 P 2 = 5!/3! = 20
  5 P 1 = 5!/4! = 5
  hence,
  no. of digits formed = 5 P 5 + 5 P 4 + 5 P 3 + 5 P 2 + 5 P 1
  = 120 + 120 + 60 + 20 + 5
  = 325
• 10 years agoHelpfull: Yes(1) No(2)
• is solution for number of digits or number of numbers.
• 10 years agoHelpfull: Yes(0) No(2)