mr ch rammohan reaches the bus stop at 5.30 pm daily...his wife comes to pick him up from the bus stop. one day he takes the early bus and reaches the bustop at 5pm. now he doesnt wait for his wife and just starts to walk towards home. he meets his wife on the way and both of them from there come together to their home. today mrs ram mohan finds that she has reached 16 minutes early than da daily time. the distance between their house and the bus top is 5 km. find for how many minutes has mr ch ram mohan been walking...??

ans: 8 mins.(when his walking speed equals to her wife speed).

16/2( i.e. it includes up+down time,so divide given time by 2)
11 years agoHelpfull: Yes(2) No(10)
8 mins is the right answer.
11 years agoHelpfull: Yes(1) No(5)
since 16 min is difference so ch rammohan covered the distance.. so saved d time of going nd cming back so 16/2 = 8 min is ans
11 years agoHelpfull: Yes(1) No(1)
Answer will be 22 minutes.
Because of Rammohans walking, they saved 16 minutes, which means they saved 8 minutes to journey and 8 minutes fro journey.
They saved 8 minutes To journey implies that they met at 5.22 instead of 5.30 as everyday

This implies that they saved 22 minutes

answer is 8 minutes..because mrs ram saves 16 min(8min(toward bus stop)+8min(towards home)) because mr ram walking 8 min towards home
10 years agoHelpfull: Yes(1) No(0)
hw it is possible wife speed= husband speed??
11 years agoHelpfull: Yes(0) No(3)
But it had not given any condition..... how can we assume their speed are equal??
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please kip in mind dat mrs rammohan takes him home using her car... my fren forgot to mention it...
11 years agoHelpfull: Yes(0) No(1)
let x be the distance from house to their new meeting point..both have travelled for equal times-> x/s1=5-x/s2, s1 and s2 are speed of wife and husband respectively. distance traveled in 14min =2x=s1*14->eq1..distance not traveled = 2(5-x)=s1*16 -> eq 2 solve for s1 and x.. x/s1 gives time.
10 years agoHelpfull: Yes(0) No(0)

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