7^101+18^101 is a multiple of
a.15
b.25
c.35
d.45

• sorry for last answer
  since, (x^n+y^n) is divisible by (x+y) for all odd values of n
  so (7^101+18^101) is divisible by (7+18=25) for n=101(odd)
  (7^101+18^101) is a multiple of 25
  ans(b)
• 11 years agoHelpfull: Yes(2) No(1)
• here on adding taking 101 common we get = 101(7+18)
  =101 (25)
  therefpre answer is 25 that is option b.
• 11 years agoHelpfull: Yes(1) No(2)
• since, (x^n+y^n) is divisible by (x+y) for all values of n
  so (7^101+18^101) is divisible by (7+18=25) for n=101
  (7^101+18^101) is a multiple of 25
  ans(b)
• 11 years agoHelpfull: Yes(0) No(1)