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Maths Puzzle
7^101+18^101 is a multiple of
a.15
b.25
c.35
d.45
Read Solution (Total 3)
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- sorry for last answer
since, (x^n+y^n) is divisible by (x+y) for all odd values of n
so (7^101+18^101) is divisible by (7+18=25) for n=101(odd)
(7^101+18^101) is a multiple of 25
ans(b) - 10 years agoHelpfull: Yes(2) No(1)
- here on adding taking 101 common we get = 101(7+18)
=101 (25)
therefpre answer is 25 that is option b. - 10 years agoHelpfull: Yes(1) No(2)
- since, (x^n+y^n) is divisible by (x+y) for all values of n
so (7^101+18^101) is divisible by (7+18=25) for n=101
(7^101+18^101) is a multiple of 25
ans(b) - 10 years agoHelpfull: Yes(0) No(1)
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