Q. What is the product of the irrational roots of the equation:
(2x-1)(2x-3)(2x-5)(2x-7)=9?

Option
(a) 3/2
(b) 4
(c) 3
(d) 3/4

• (2x - 1) (2x - 3) (2x - 5) (2x - 7) = 9
  Let 2x - 4 = y
  => (y + 3) (y + 1) (y - 1) (y - 3) = 9
  => (y^2 - 1) (y^2 - 9) = 9
  => y^4 - 10y^2 + 9 = 9
  => y^2 (y^2 - 10) = 0
  => y = 0 or ± √(10)
  => 2x - 4 = ± √(10)
  => x = (1/2) [4 ± √(10)]
  => product of the irrational roots
  = (1/2)^2 * [4 + √(10)] [4 - √(10)]
  = (1/4) * 6
  = 3/2.
  so,the answer is 3/2.......
• 10 years agoHelpfull: Yes(8) No(3)
• How cum its (1/2)^2 in the 11th statement..I think it must be
  =>(1/2)*[4+sq(10)][4-sq(10)]
  =>(1/2)*[16-10]
  =>6/2
  =>3
• 10 years agoHelpfull: Yes(3) No(4)