Q. In a farm 50 hens lays 200 eggs in 2 days, how many days that 20 hens to lay 400 eggs?

• 50 hens --- 200 eggs ---- 2 days
  50 hens --- 100 eggs ---- 1 day
  1 hen --- 2 eggs ---- 1 day
  20 hens --- 40 eggs ---- 1 day
  So 20 hens can lay 40 eggs in 1 day
  then 20 hens can lay 400 eggs in 10 days (40*10=400)
• 11 years agoHelpfull: Yes(81) No(8)
• 50*2*400=20*200*x
  so
  x=10days
• 11 years agoHelpfull: Yes(36) No(4)
• time and work related
  MDH/W=const
  50*2/200=20*x/400
  x=10days.
• 11 years agoHelpfull: Yes(14) No(1)
• Ans is 10 days.
  50 Hens 200 Eggs in 2 Days
  50 Hens 100 Eggs in 1 Day
  1 Hen 2 Eggs in 1 Day
  20 Hens 40 Eggs in 1 Day
  20 Hens 400 Eggs in 10 Days.
  
  So Ans is 10 days
• 11 years agoHelpfull: Yes(8) No(1)
• 50 hens 200 e in 2 days
  20 hens in 1 days 40 eggs
  then 400 eggs in 10 days
• 11 years agoHelpfull: Yes(6) No(1)
• M*D/W = M*D/W
  50*2/200 = 20*x/400
  x= 100 days
• 11 years agoHelpfull: Yes(4) No(6)
• 10 days
  
  50 hens 200 eggs n 2 days means 100 eggs in a day
  means each hen can lay 2 eggs a day
  so 20 hens can lay 40 eggs per day
  so 400 eggs in 10 days
• 11 years agoHelpfull: Yes(2) No(0)
• 50 hens=200 eggs in 2 days.
  50 hens=100 eggs in 1 day.
  1 hen=100/50= 2 eggs in 1 day.
  so 20 hens= 40 eggs in 1 day.
  so it takes 10 days..
• 11 years agoHelpfull: Yes(2) No(1)
• H1=50 W1=200 D1=2DAYS
  H2=20 W2=400 D2=?
  BY PUTTING FORMULA H1*W2*D1/H2*W1*D2
  D2=50*400*2/20*200 =10ans..
  
• 10 years agoHelpfull: Yes(2) No(0)
• Hey Guys, for that type of ques:
  always Use the following Formulae:
  |------------------------------------|
  |M1*D1*w2 = M2*D2*W1 |
  |-------------------------------------|
  
  eg:- Here M1= 50; D1= 2; W1=200; M2= 20; d2= ?? ; W2= 400
  put all values in the above Formulae
  50 *2*400 = 20 * d2* 200
  => D2= 10 ans
  With Regards
  Kumar Amit
  https://www.facebook.com/kumaramitaryan ( Feel free To ask any Thing )
• 9 years agoHelpfull: Yes(2) No(0)
• 50hens-200eggs-2days
  1hen for 2days=200/50=4eggs
  1hen for 1day=2eggs-->(1)
  20hens-400eggs-xdays
  1hen for 1day=2eggs (as per statement 1)
  20hens for 1day=40eggs
  20hens for xdays=400eggs
  40x=400
  x=10
  
• 11 years agoHelpfull: Yes(1) No(1)
• From the Given details:
  50 hens takes 2 days for laying 200 eggs,
  50 hens takes 1 day for laying 100 eggs,
  so 1 hen lays 2 eggs in 1 day.
  
  Coming to the problem:
  20 hens lays 40 eggs in 1 day
  so 20 hens may lays 400 eggs in 10 days.
  Answer is 10 days..
  any information mail to: matheswarenkrm@gmail.com, kanthsenthil007@gmail.com
  
• 11 years agoHelpfull: Yes(1) No(0)
• 10 days.
  simple math rule apply(2*50*400)/(20*200)
• 11 years agoHelpfull: Yes(1) No(0)
• Friends logic here is very simple ..
  
  50 hens lays 200 eggs in 2 days [ it means 100 per day (it means each hen lays 2 eggs) ]
  
  therefor 20 hens lays 40 eggs per day , therefore 400/40 = 10 days .
• 10 years agoHelpfull: Yes(1) No(0)
• i got this question in amcat cts exam
• 10 years agoHelpfull: Yes(1) No(0)
• 50 hen * 2 Egg * 2 day =200
  20hen * 2Egg * 10days=400
• 9 years agoHelpfull: Yes(1) No(0)
• time and work method
  (M1*D1)/W1 = (M2*D2)/W2
  where
  M =members
  D = days
  W = work
  now see here
  M1= 50 hens
  D1 = 2 days
  w1 = 200 eggs
  and
  
  M2 = 20 hens
  D2 = ? lets take x
  W2 = 400 eggs
  
  
  (50*2)/200 = (20*x)/400
  after calculation x = 10
  so that 20 hens takes 10 days to lay 400 eggs
  
• 9 years agoHelpfull: Yes(1) No(0)
• 50hens lays 200 eggs in 2 days so 200/50=4 . 4 eggs are laid by 1 hen in 2 days.so 1 hen can lay 2 eggs per day. so 20 hens can lay 40 eggs per day so 40* 10=400. It takes 10 days to lay 400 eggs by 20 hens
• 11 years agoHelpfull: Yes(0) No(2)
• 50hens=>200eggs=>2days;
  50hens=>100eggs=>1days;
  
  1 hen=100/50 =>2eggs
  
  20hen=>20*2=40eggs (in 1day)
  
  no of days= 400(total egg)/40(in 1 day)
  
  no of days=10 ;
• 11 years agoHelpfull: Yes(0) No(1)
• 1 day a hen lays 2 egg hence 2 days 50 hens lays 200 egg therefore 20 hens lays per day 0 eggs then it takes 10 days for 400 eggs
  
• 11 years agoHelpfull: Yes(0) No(0)
• 10 days to lay eggs.....
• 11 years agoHelpfull: Yes(0) No(0)
• 50 hens 200 eggs 2 days..
  20 hens 400 eggs ? days..
  simplify this,we get 10 days.
• 11 years agoHelpfull: Yes(0) No(1)
• 50 hens lays 200 eggs in 2days then 20hens to lay 400eggs int 10days .
• 11 years agoHelpfull: Yes(0) No(0)
• By applying chain rule we can get the answer.The process is like this
  
  Hens Eggs Days
  ----------------------
  50 ----> 200 --->2
  20 ----> 400 --->?
  
  so we have to find the days right
  first put the days which is above the ? mark line and
  then now compare hens and days lines we will get it like this
  
  hens days
  ------------
  50 2
  20 ?
  
  now assume for 50 hens only 2 days
  for 20 hens it may take more days then what 50 hens take so (more / less)according to chain rule,so we have 50/20
  like this compare eggs and days line also...
  so finally we got like this 2*50/20*400/200
  after solving we got 10 days this is the answer folks :)
  
• 10 years agoHelpfull: Yes(0) No(0)
• 50hens --------200eggs-------2days
  20hens ---------400eggs--------??
  friends see here 50 hens are laying 200 eggs in 2days then 20 hens will lay 400 eggs in more number of days .
  so (more/less)
  =>(50/20)(400/200)*2
  =10
  for these kind of sums if you consider more/less it will be easy
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• 50*2/200=20*x*/400=>10days
• 10 years agoHelpfull: Yes(0) No(0)
• 50 hens in 1 day=200 eggs
  1 hen in 1 day=4 eggs
  so,
  20 hen in 1 day=80
  but we need to find ,in how many days 20 hens lay 400 eggs ,so 5*80=400
  so it takes 5 days for 20 hens to lay 400 eggs
• 10 years agoHelpfull: Yes(0) No(0)
• 10 days
  50*2/200=20*x/400
  x=10
• 10 years agoHelpfull: Yes(0) No(0)
• Ans is 10 days
  
• 9 years agoHelpfull: Yes(0) No(0)
• 50 hens - 200 eggs - 2 days
  50 hens - 100 eggs - 1 day
  1 hen - 2 egg - 1 day
  20 hens - 40 eggs - 1 day
  then 400 eggs will be laid in 400/40= 10 days by 20 hens.
• 9 years agoHelpfull: Yes(0) No(0)
• chain rule mdh /w = c
  50*2*400/(200*20) = x = 10days
• 9 years agoHelpfull: Yes(0) No(0)
• 50 Hens - - - 2 Days - - - 200 Eggs
  1 Hen --------- 1 Day-------200/(50*2) = 2 Eggs
  20 Hens - - - -1 Day - - - - 2 *20 = 40 Eggs
  So, For 400 Eggs They Will Take 10 Days :)
• 9 years agoHelpfull: Yes(0) No(0)
• 10 days since 50*2*400=20*200*x
  solving for x we get 10 days
• 9 years agoHelpfull: Yes(0) No(0)
• Ans:10 Day
  
• 9 years agoHelpfull: Yes(0) No(0)
• using chain rule.
  hens days eggs
  50 2 200
  20 x 400
  50x2x400=20xXx200
  40000=4000x
  x=10
• 9 years agoHelpfull: Yes(0) No(0)
• (50*2)/200=(20*x)/400
  solving the above equation we get x=10days
• 9 years agoHelpfull: Yes(0) No(0)
• 10 days
  50 hens 2 day 200 eggs
  50 hens 1 day 100 eggs
  20 hens 1 day 40 eggs(100/50*2)
  so 20 hens 400 eggs in 10 day(40*10=400)
• 9 years agoHelpfull: Yes(0) No(0)
• (50*2)/200 =(20*D)/400
  D=10
• 9 years agoHelpfull: Yes(0) No(0)
• 50 hens=200 eggs in 2 days
  5 hens =20 eggs in 2 days
  20 hens= 80 eggs in 2 days
  20 hens=400 eggs in 10 days
  10 days
• 9 years agoHelpfull: Yes(0) No(0)
• Hen Ratio 20:50
  Egg Ratio 200:400
  Day Ratio 2:x
  X=500*400*2/200*20
  X=10
  
• 9 years agoHelpfull: Yes(0) No(0)
• 50/200=40/2=20
  20/400=20/2=10
• 8 years agoHelpfull: Yes(0) No(0)
• 10
  2 days -200 eggs
  => 1 day-100 eggs
  100 eggs by 50 hen => 2 eggs by 1 hen in 1 day
  given 20 hen =>20*2=40 eggs per day
  to get 400 eggs we need 400/40=10 days
  
  
  
• 8 years agoHelpfull: Yes(0) No(0)
• Deccrease in number of eggs will decrease the days required, so divide.
  While decrease in number of hen will increase the number of days required, so multiply.
  So
  50hen---200eggs = 2 days
  01hen---200eggs = 2*50 days
  01hen---1 eggs = (2*50)/200 days
  20hen--- 400eggs = (2*50*400)/(200*20)
  = 10 days
• 6 years agoHelpfull: Yes(0) No(0)
• (M*D*H)/W = (m*d*h)/w
  50*2/200 = 20*d/400
  d = 10
• 6 years agoHelpfull: Yes(0) No(0)
• 50 hens =200 eggs in 2 days
  1 day, 50 hens 100 eggs
  1hen = 100/50=2
  20 hens *2 per day = 40
  400/40 = 10
  10 days
• 4 years agoHelpfull: Yes(0) No(0)