Q. What is the missing numbers of the following sequence
2, 10, ?, 68, 130, ?.

• Ans is 30 & 222.
  1^3+1=2
  2^3+2=10
  3^3+3=30
  4^3+4=68
  5^3+5=130
  6^3+6=222
• 11 years agoHelpfull: Yes(2) No(0)
• ans= 30,222
  1^3 +1 = 2
  2^3 +2 = 10
  3^3 +3 = 30
  4^3 +4 = 68
  5^3 +5 = 130
  6^3 +6 = 222
• 11 years agoHelpfull: Yes(1) No(0)
• 68=4^3+4,130=5^3+5,so preceeding no 68 is must be 3^3+3=30
• 11 years agoHelpfull: Yes(0) No(0)