Q. The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 147, what is the difference between the ages of Patrick and Monica?

• let their ages are 9x,15x and 25x respectively.
  difference between the ages of Patrick and Monica = 25x-9x=16x where
  49x=147 or x=3
  so diff in ages = 16x=16*3=48 yrs
• 11 years agoHelpfull: Yes(3) No(0)
• let age of patrick, Michael and Monica be x, y and z respectively
  x:y=3:5
  y:z=3:5
  x:y:z = 9:15:25
  given x+y+z=147
  so x= 9*147/(9+15+25)= 9*147/49= 9*3=27
  similarly z=75
  difference= 75-27= 48
• 11 years agoHelpfull: Yes(2) No(2)
• The difference between ages of monika and pratik is 48.
  The common person given in ratio is Michael so, make his part equal for both ratios. to make them equal,
  3*(3:5) & 5*(3:5) so, parts for Pratik, Michael, & Monika are 9x,15x,25x respectively.
  Diffrence between age of Pratik and monika is 25-9=16x.
  Now, sum of their ages =147 Therefore, (9+15+25)x=147
  49x=147
  x=3
  So, the diffrence between their ages=16x=16*3=48
• 11 years agoHelpfull: Yes(1) No(1)
• 48
  x:y:z=9:15:25
  (x+y+z)X=147
  X=3
  75-27=48
• 11 years agoHelpfull: Yes(0) No(1)
• answer 48
  3:5 and 3:5
  is 9:15:25
  so 9+15+25 =49
  147/49=3
  25-9=16
  16*3=48
  so answer 48
• 11 years agoHelpfull: Yes(0) No(1)